Definition
Independent Set to Proportional Winner Determination
There is a polynomial-time many-one reduction from the Independent Set problem to the proportional winner determination decision problem:
Construction
Given an independent set instance
Create one candidate
Construct the voters as follows:
- For every edge
, create one edge voter with approval set - For every vertex
, create private voters, each with approval set
Repeated approval sets represent distinct voters. Output the proportional approval voting decision instance with candidate set
The private voters fill each vertex’s degree deficit. Consequently, every candidate is approved by exactly
Score Formula
For
and let
be the edges induced by
| selected approved candidates | |||
|---|---|---|---|
| voter contribution |
Every selected candidate supplies a base contribution of
The target
Correctness
The graph
Correctness
Forward
Suppose that
has an independent set with . Choose a subset with and let be the corresponding committee. Since is independent, The score formula gives
Hence the constructed proportional winner determination instance is a yes-instance.
Backward
Suppose that a size-
committee has PAV score at least . The score formula gives Thus the threshold can be reached only when
. No two vertices of are adjacent, so is an independent set of size and is a yes-instance.
Running Time
The construction creates
private voters. Since
NP-completeness
The reduction proves that proportional winner determination is NP-hard. Together with membership in NP, established in the decision-problem note, this proves NP-completeness.